Condition使用,

Condition使用,

面试题:写一个固定容量同步容器,拥有put和get方法,以及getCount方法,
    能够支持2个生产者线程以及10个消费者线程的阻塞调用

有两种方法

1.使用wait和notify/notifyAll来实现

import java.util.LinkedList;
import java.util.concurrent.TimeUnit;

public class MyContainer1<T> {
    final private LinkedList<T> lists = new LinkedList<>();
    final private int MAX = 10; //最多10个元素
    private int count = 0;


    public synchronized void put(T t) {
        while(lists.size() == MAX) { //想想为什么用while而不是用if?
            try {
                this.wait(); //effective java
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }

        lists.add(t);
        ++count;
        this.notifyAll(); //通知消费者线程进行消费
    }

    public synchronized T get() {
        T t = null;
        while(lists.size() == 0) {
            try {
                this.wait();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
        t = lists.removeFirst();
        count --;
        this.notifyAll(); //通知生产者进行生产
        return t;
    }

    public static void main(String[] args) {
        MyContainer1<String> c = new MyContainer1<>();
        //启动消费者线程
        for(int i=0; i<10; i++) {
            new Thread(()->{
                for(int j=0; j<5; j++) System.out.println(c.get());
            }, "c" + i).start();
        }

        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }

        //启动生产者线程
        for(int i=0; i<2; i++) {
            new Thread(()->{
                for(int j=0; j<25; j++) c.put(Thread.currentThread().getName() + " " + j);
            }, "p" + i).start();
        }
    }
}

2.使用Lock和Condition来实现
 对比两种方式,Condition的方式可以更加精确的指定哪些线程被唤醒

import java.util.LinkedList;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;

public class MyContainer2<T> {
    final private LinkedList<T> lists = new LinkedList<>();
    final private int MAX = 10; //最多10个元素
    private int count = 0;

    private Lock lock = new ReentrantLock();
    private Condition producer = lock.newCondition();
    private Condition consumer = lock.newCondition();

    public void put(T t) {
        try {
            lock.lock();
            while(lists.size() == MAX) { //想想为什么用while而不是用if?
                producer.await();
            }

            lists.add(t);
            ++count;
            consumer.signalAll(); //通知消费者线程进行消费
        } catch (InterruptedException e) {
            e.printStackTrace();
        } finally {
            lock.unlock();
        }
    }

    public T get() {
        T t = null;
        try {
            lock.lock();
            while(lists.size() == 0) {
                consumer.await();
            }
            t = lists.removeFirst();
            count --;
            producer.signalAll(); //通知生产者进行生产
        } catch (InterruptedException e) {
            e.printStackTrace();
        } finally {
            lock.unlock();
        }
        return t;
    }

    public static void main(String[] args) {
        MyContainer2<String> c = new MyContainer2<>();
        //启动消费者线程
        for(int i=0; i<10; i++) {
            new Thread(()->{
                for(int j=0; j<5; j++) System.out.println(c.get());
            }, "c" + i).start();
        }

        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }

        //启动生产者线程
        for(int i=0; i<2; i++) {
            new Thread(()->{
                for(int j=0; j<25; j++) c.put(Thread.currentThread().getName() + " " + j);
            }, "p" + i).start();
        }
    }
}

 

面试题:写一个固定容量同步容器,拥有put和get方法,以及getCount方法,
能够支持2个生产者线程以及10个消费者线程的阻塞调…

 

import java.util.LinkedList;
import java.util.concurrent.TimeUnit;

public class MyContainer1<T> {
    final private LinkedList<T> lists = new LinkedList<>();
    final private int MAX = 10; //最多10个元素
    private int count = 0;


    public synchronized void put(T t) {
        while(lists.size() == MAX) { //想想为什么用while而不是用if?
            try {
                this.wait(); //effective java
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }

        lists.add(t);
        ++count;
        this.notifyAll(); //通知消费者线程进行消费
    }

    public synchronized T get() {
        T t = null;
        while(lists.size() == 0) {
            try {
                this.wait();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
        t = lists.removeFirst();
        count --;
        this.notifyAll(); //通知生产者进行生产
        return t;
    }

    public static void main(String[] args) {
        MyContainer1<String> c = new MyContainer1<>();
        //启动消费者线程
        for(int i=0; i<10; i++) {
            new Thread(()->{
                for(int j=0; j<5; j++) System.out.println(c.get());
            }, "c" + i).start();
        }

        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }

        //启动生产者线程
        for(int i=0; i<2; i++) {
            new Thread(()->{
                for(int j=0; j<25; j++) c.put(Thread.currentThread().getName() + " " + j);
            }, "p" + i).start();
        }
    }
}

有两种方法

2.使用Lock和Condition来实现
 对比两种方式,Condition的方式可以更加精确的指定哪些线程被唤醒

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